Example 2 - Chapter 12 Class 11 - Intro to Three Dimensional Geometry (Term 2)
Last updated at Jan. 31, 2020 by Teachoo
Last updated at Jan. 31, 2020 by Teachoo
Transcript
Example 2 Find the octant in which the points (–3, 1, 2) and (–3, 1, – 2) lie. (−3, 1, 2) Here x is negative, y is positive and z is positive So it lies in II octant. (ii) (−3, 1, −2) Here x is negative, y is positive and z is negative. So it lies in VI octant.
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